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equation of an line
- Thread starter Kwesi74
- Start date
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Gene
Stick with
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------------------
Gene
Hello, Kwesi74!
Evidently, you're not familiar with the Point-Slope Formula.
. . What have you been taught? .Just the Slope-Intercept form: . \(\displaystyle y \,= \,mx + b\) ?
. . The equation (so far) is; .\(\displaystyle y \,= \,\frac{1}{2}x + b\)
Since \(\displaystyle (2,5)\) is on the line, we have: \(\displaystyle x = 2,\;y = 5.\)
Plug those into our equation: . \(\displaystyle 5 \;= \;\frac{1}{2}(2) + b\quad\Rightarrow\quad b = 4\)
There! . . . The equation is: .\(\displaystyle y \;= \;\frac{1}{2}x + 4\)
Evidently, you're not familiar with the Point-Slope Formula.
. . What have you been taught? .Just the Slope-Intercept form: . \(\displaystyle y \,= \,mx + b\) ?
We are given the slope: \(\displaystyle m \,= \,\frac{1}{2}\)Find the an equation of a line through the point (2,5) with slope 1/2
. . The equation (so far) is; .\(\displaystyle y \,= \,\frac{1}{2}x + b\)
Since \(\displaystyle (2,5)\) is on the line, we have: \(\displaystyle x = 2,\;y = 5.\)
Plug those into our equation: . \(\displaystyle 5 \;= \;\frac{1}{2}(2) + b\quad\Rightarrow\quad b = 4\)
There! . . . The equation is: .\(\displaystyle y \;= \;\frac{1}{2}x + 4\)