Equations/Functions

davehogan

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Sep 5, 2013
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Some simple equations mystify me. I am asked to sketch the following function on a graph. "f(x)=(x-2)2(x+1)", but I can't get this right. The answer shows a cubic graph and it goes from 2,0 to 0,4 then down to -1, 0. now I understand this except the move to 0,4. I know that -22 is 4, but that is just dealing with first term (x-2)2. Then we go on with the next term (x+1). I'm really confused with this.
 
Some simple equations mystify me. I am asked to sketch the following function on a graph.
"f(x)=(x-2)2(x+1)", but I can't get this right. The answer shows a cubic graph and it goes from 2,0 to 0,4 then down to -1, 0.
now I understand this except the move to 0,4. I know that -22 is 4, but that is just dealing with first term (x-2)2.
Then we go on with the next term (x+1). I'm really confused with this.

What are you doing typing coordinates without the required parentheses!? And why do you think -22 is 4? It's supposed to be (-2)2 = 4.   \displaystyle \ \ <----Edit

Type all of your coordinates using parentheses.

The y-intercept is where x = 0.   f(0) = (02)2(0+1) = (2)2(1) = (4)(1)=4\displaystyle \ \ f(0) \ = \ (0 - 2)^2(0 + 1) \ = \ (-2)^2(1) \ = \ (4)(1) = 4

So, the y-intercept is (0,4).
 
Last edited:
Some simple equations mystify me. I am asked to sketch the following function on a graph. "f(x)=(x-2)2(x+1)", but I can't get this right. The answer shows a cubic graph and it goes from 2,0 to 0,4 then down to -1, 0. now I understand this except the move to 0,4. I know that -22 is 4, but that is just dealing with first term (x-2)2. Then we go on with the next term (x+1). I'm really confused with this.

The way you wrote your question is a little confusing. When you say "...it goes from 2,0 to 0,4 then down to -1, 0" I assume you are referring to the coordinates (2,0), (0,4), and (-1,0). These are simply the x and y intercepts. Do you know how to find the x and y intercepts of a function?
 
What are you doing typing coordinates without the required parentheses!? And why do you think -22 is 4? It's supposed to be (-22) = 4.

Type all of your coordinates using parentheses.

The y-intercept is where x = 0.   f(0) = (02)2(0+1) = (2)2(1) = (4)(1)=4\displaystyle \ \ f(0) \ = \ (0 - 2)^2(0 + 1) \ = \ (-2)^2(1) \ = \ (4)(1) = 4

So, the y-intercept is (0,4).


I obviously need to revise on coordinates. I tried (x=-2) and came up with (-16) which is clearly wrong. Thanks for explaining the coordinates (0,4).
 
What are you doing typing coordinates without the required parentheses!? And why do you think -22 is 4? It's supposed to be (-22) = 4.

Actually, no. (22)=4\displaystyle (-2^2)= -4. What you mean is (2)2=4\displaystyle (-2)^2= 4.

Type all of your coordinates using parentheses.

The y-intercept is where x = 0.   f(0) = (02)2(0+1) = (2)2(1) = (4)(1)=4\displaystyle \ \ f(0) \ = \ (0 - 2)^2(0 + 1) \ = \ (-2)^2(1) \ = \ (4)(1) = 4

So, the y-intercept is (0,4).
 
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