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equations with fractions
- Thread starter reberobi
- Start date
D
Deleted member 4993
Guest
I have a questions about this problem do I multiply the riciprical on the outside then do the same for the fraction inside the ( )
3/4 (-12x -1/2) = -12
Yes...
If I were to do this problem, I would multiply both sides by (1/(3/4) = ) 4/3 and further isolate and simplify.
do I multiply the riciprical on the outside then do the same for the fraction inside the ( )
IF I understand your question correctly, the answer is NO. You do not multiply both the (3/4) term and the (-12x -1/2) by (4/3). You multiply each side of the equation by (4/3) just one time.
3/4 (-12x -1/2) = -12
(4/3)[(3/4) (-12x -1/2)] = (4/3)[-12]
(-12x -1/2)] = -16
D
Deleted member 4993
Guest
IF I understand your question correctly, the answer is NO. You do not multiply both the (3/4) term and the (-12x -1/2) by (4/3). You multiply each side of the equation by (4/3) just one time.
3/4 (-12x -1/2) = -12
(4/3)[(3/4) (-12x -1/2)] = (4/3)[-12]
(-12x -1/2)] = -16
You are correct - I misunderstood the description...