Agent Smith
Junior Member
- Joined
- Oct 18, 2023
- Messages
- 84
I suspect it represents someone who needs help -- badly!
Pythagoras (requiescat in pace) has been the brand ambassador for mathematics and is, at least should be, a constant fixture on math sites, looks especially good on the homepage (kinda gives the game away). Cogito, 9 outta 10 times peeps visiting this site wouldn't double check the equation (which is incorrect if Pythagoras theorem was intended) and would simply miss the error. I got lucky, that doesn't happen everyday.I suspect it represents someone who needs help -- badly!
On the other hand, it's a perfectly valid equation; it just reminds you of another, with a particular meaning. No one is saying what a, b, and c are, or even whether the equation is true.
(You wouldn't believe the number of people I run across who think that [imath]a^2 + b^2 = c^2[/imath], by itself, is the Pythagorean theorem.)
a2×b2=(ab)2=c2 isn't quite the equation a mathematician would be impressed by.
Since we're talking about errors ... your Latin is not quite right. First, the spelling for the infinitive "to be" is "errare", not "errara"; second, "cogito" means "think" in a different sense than you are using it for here. There are lots of different words for "think" in different senses.Cogito, 9 outta 10 times peeps visiting this site wouldn't double check the equation (which is incorrect if Pythagoras theorem was intended) and would simply miss the error. I got lucky, that doesn't happen everyday.
I generally describe him as a cult leader.Pythagoras was a numerologist and a shame for mathematics in my opinion. I would ignore "his" theorem completely and insist on calling it the cosine theorem. Pythagoras's theorem wasn't even "his" theorem since the Babylonians (or was it the Assyrians?) already knew it.
Perhaps [imath]a^2 + b^2 = \frac{E}{m} = c^2[/imath].
[imath]e^{i \pi} + 1^{i \pi} = 0^{i \pi}[/imath]Single most impressive and expressive self-contained formula in my book is Euler's identity.