Evaluating Help Stuck

[Ryan Rigdon]

I am stuck here. been on the problem for over an hour cant see what to do next. here is my work thus far.

 

[Ryan Rigdon]

i tried it and this is what i came up with. hope its right.

 

[Deleted member 4993]

$\displaystyle \int e^u\sin(u)du \ = \ -e^u\cdot cos(u) \ + \ \int e^u\cos(u)du$

$\displaystyle \int e^u\sin(u)du \ = \ -e^u\cdot cos(u) \ + [e^u\cdot sin(u)\ - \ \int e^u\sin(u)du$

$\displaystyle \int e^u\sin(u)du \ = \ \frac{1}{2}\cdot \left[\ -e^u\cdot cos(u) \ + e^u\cdot sin(u)\right ]$

 

[Ryan Rigdon]

thanx for the hint Subhotosh Khan