N nikchic5 Junior Member Joined Feb 16, 2006 Messages 106 Jun 11, 2007 #1 Hello. Can I please get help? (I have a test coming up!) Evalute the integral... the integral of 4x-2 / 3(x-1)^2 dx Thanks so much!
Hello. Can I please get help? (I have a test coming up!) Evalute the integral... the integral of 4x-2 / 3(x-1)^2 dx Thanks so much!
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jun 11, 2007 #2 Which is it? \(\displaystyle \L 4x - \frac{2}{{3\left( {x - 1} \right)}}\quad or\quad \frac{{4x - 2}}{{3\left( {x - 1} \right)}}\)
Which is it? \(\displaystyle \L 4x - \frac{2}{{3\left( {x - 1} \right)}}\quad or\quad \frac{{4x - 2}}{{3\left( {x - 1} \right)}}\)
N nikchic5 Junior Member Joined Feb 16, 2006 Messages 106 Jun 11, 2007 #3 It is the second one. Thanks so much[/img]
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jun 11, 2007 #4 \(\displaystyle \L \frac{{4x - 2}}{{3\left( {x - 1} \right)}} = \frac{{4x}}{{3\left( {x - 1} \right)}} - \frac{2}{{3\left( {x - 1} \right)}}\)
\(\displaystyle \L \frac{{4x - 2}}{{3\left( {x - 1} \right)}} = \frac{{4x}}{{3\left( {x - 1} \right)}} - \frac{2}{{3\left( {x - 1} \right)}}\)
