G

#### Guest

##### Guest

i have to solve this problem:

sqrt(1+2x+x^2) = 2

what i did:

1^(0.5)+ 2x^(0.5)+x= 2

2x^0.5+x = 2-1^0.5

then from here i am not sure to solve this problem do i have to do :roll:

Thanks in advance

G

i have to solve this problem:

sqrt(1+2x+x^2) = 2

what i did:

1^(0.5)+ 2x^(0.5)+x= 2

2x^0.5+x = 2-1^0.5

then from here i am not sure to solve this problem do i have to do :roll:

Thanks in advance

\(\displaystyle \L

\sqrt{x^2+2x+1}=2 \Rightarrow (x^2+2x+1)^{\frac{1}{2}} = 2

\\\)

Now square both sides:

\(\displaystyle \L((x^2+2x+1)^{\frac{1}{2}})^{2} = 2^2\\

\Rightarrow

(x^2+2x+1)^{\frac{2}{2}} = 4\\

\Rightarrow x^2+2x+1 = 4\\\)

Now use your knowledge of quadratics to solve.

G

daon said:

\(\displaystyle \L

\sqrt{x^2+2x+1}=2 \Rightarrow (x^2+2x+1)^{\frac{1}{2}} = 2

\\\)

Now square both sides:

\(\displaystyle \L((x^2+2x+1)^{\frac{1}{2}})^{2} = 2^2\\

\Rightarrow

(x^2+2x+1)^{\frac{2}{2}} = 4\\

\Rightarrow x^2+2x+1 = 4\\\)

Now use your knowledge of quadratics to solve.