x = log(128)/log(5)5^x=128
125^y=32
then
(2x+y)/(4y-x) = ?
i tried writing in terms of each other but could not solve
the answer is -47 , but dont know how to obtain it
5^x=128
125^y=32
then
(2x+y)/(4y-x) = ?
i tried writing in terms of each other but could not solve
the answer is -47 , but dont know how to obtain it
x = log(128)/log(5)
y = log(32)/log(125)
Are you allowed to use logs?
If so, above will give -47
If you don't choose to use logarithms, you can rewrite the equations as
5^x = 2^7
5^(3y) = 2^5.
Then raise the first equation to the 5th power, and the second to the 7th power, and you can find the ratio y/x. Use that in the requested expression.