S Sam007 New member Joined Mar 4, 2019 Messages 15 Mar 4, 2019 #1 Hi everyone, I found this question very difficult to understand. Any help would be appreciated. This is what I got so far
Hi everyone, I found this question very difficult to understand. Any help would be appreciated. This is what I got so far
H HallsofIvy Elite Member Joined Jan 27, 2012 Messages 7,760 Mar 5, 2019 #2 You STILL have the original function, just with two "0"s added. I don't think that was the intention of the problem!
You STILL have the original function, just with two "0"s added. I don't think that was the intention of the problem!
