f(x)=-1/4(x^5+2x^4-15x^3-40x^2+4x+48)

[dani143]

find the x-intercepts
symmetry
max and min points
slope of function

find the equation of :
secant from x=-3 to x=2
tangent at x=1

 

[dani143]

f(x)=-1/4(x^5-x^4-13x^3+x^2+48x+36)

SORRY .... ok so i plug in numbers at f(x) and after finding F(x)=0
i got the x-intercepts which are x=3(order2), -2(iorder2), and -1
but i dont know how to get y-intercept

 

[dani143]

the increase is xE(-2,-1.5)u(1,3)
the decrease is xE(-1.5,1)u(3,infinity)

positive(above x-axis|) are xE(-infinity,-1)
negative (below x-axis) are xe(-1,infinity)

 

[dani143]

i dont know the slope of function... all i know is slope is y=delta y/ delta x

please help with findin the functions symmetry and slope.. thank you

 

[stapel]

i dont know the slope of function... all i know is slope is y=delta y/ delta x

please help with findin the functions symmetry and slope.. thank you

To examine the symmetry, start by examining the graph.

To find the equation for the "slope at a point", find the derivative.

 

[HallsofIvy]

SORRY .... ok so i plug in numbers at f(x) and after finding F(x)=0
i got the x-intercepts which are x=3(order2), -2(iorder2), and -1
but i dont know how to get y-intercept

It's hard to believe you can't get the y intercept. The graph crosses the y- axis when x= 0. What is y when x= 0?

 

[dani143]

It's hard to believe you can't get the y intercept. The graph crosses the y- axis when x= 0. What is y when x= 0?

So when x=0 , y= -9???
F(0)= -1/4 (x-3)^2(x+2)^2(x+1)
=-1/4 (9)(4)(1)
= -9

 

[dani143]

One last thing.. is my answer for increase and decrease, + AND - Right? ??