f(x)=4/1 + x^2 = 2 (?)

[Dragon King]

Is there an easier way to figuring these kinds of questions out so they don't take so long to do on test?

f(x)=4/1 + x^2
f(x)=4/1 + -1^2 = 2
f(x)=4/1 + x^2 = 2 (?)
I can't figure out the second number that equals 2 for the first problem

f(x)= x^2 - 2x + 1
f(x)=2^2 - 2(2) + 1 = 4 - 4 + 1= 1
f(x)=0^2 - 2(0) + 1 = 0 - 0 + 1= 1

I know you have to find 2 numbers that give you the same answer.

Also how do you find the inverse of a graph if all you have is the graph and no equation? My professor showed me a method, but i'm not sure that is working quite as well for the one graph I am having a problem on.
I can't show the graph, this is my first time on this site, given to me by a classmate. Please help.

 

[stapel]

I'm sorry, but I can't tell what the actual question is. Assuming you mean f(x) to be 4/(1 + x² (and not 4/1 + x² = 4 + x², as posted), what are you supposed to be doing with the function?

Please reply with the full text of the exercise, including the instructions and an explanation of your steps. Thank you.

Eliz.