mathdad Full Member Joined Apr 24, 2015 Messages 941 May 14, 2019 #1 Factor completely. x^4 - 1 (x^2 - 1)(x^2 + 1) (x - 1)(x + 1)(x^2 + 1) The factor (x^2 + 1) is already in lowest terms. Yes?
Factor completely. x^4 - 1 (x^2 - 1)(x^2 + 1) (x - 1)(x + 1)(x^2 + 1) The factor (x^2 + 1) is already in lowest terms. Yes?
mathdad Full Member Joined Apr 24, 2015 Messages 941 May 14, 2019 #3 topsquark said: Yes. -Dan Click to expand... Very good.
