T tsh44 Junior Member Joined Sep 4, 2005 Messages 67 May 6, 2006 #1 Hello how would you simply these factorial expressions? a) n!/ (n-1)! b) (n+1)!/ (n-1)! I'm not sure where to start. Thanks.
Hello how would you simply these factorial expressions? a) n!/ (n-1)! b) (n+1)!/ (n-1)! I'm not sure where to start. Thanks.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 May 6, 2006 #2 \(\displaystyle n!=n(n-1)(n-2)(n-3)..................\) \(\displaystyle (n-1)!=(n-1)(n-2)(n-3)..................\) Therefore, \(\displaystyle \frac{n\sout{(n-1)(n-2)(n-3)}......}{\sout{(n-1)(n-2)(n-3)}.......}=n\) Try the other one using this technique.
\(\displaystyle n!=n(n-1)(n-2)(n-3)..................\) \(\displaystyle (n-1)!=(n-1)(n-2)(n-3)..................\) Therefore, \(\displaystyle \frac{n\sout{(n-1)(n-2)(n-3)}......}{\sout{(n-1)(n-2)(n-3)}.......}=n\) Try the other one using this technique.
