factoring 15x^2 + 26x + 8: Did I do this one right?

No, that's not correct. Expand it out. Do you get the origianl quadratic?.

Let's see:

Your quadratic is \(\displaystyle \L\\15x^{2}-26x-8\)

You have \(\displaystyle \L\\(5x+2)(3x+4)=15x^{2}+26x+8\)

Nope. Wrong signs.
 
You have an x and a y. Why is that?. But, nonetheless, that's incorrect.

What two numbers when added equal -26 and when multiplied equal -120(15*-8=-120)?.

Let's see.....how about 4 and -30.

\(\displaystyle \L\\15x^{2}-30x+4x-8\)

Now continue?.
 
You appear to have changed the exercise since your original post, since earlier replies refer to the negative signs which are no longer in evidence...? :shock:

jenzbears said:
Factor 15x^2 + 26x + 8
Click to expand...
You might want to read the replies you receive. If this new version of the exercise is the correct one, then you've already been given the answer! :wink:

Eliz.
 
stapel said:
You might want to read the replies you receive. If this new version of the exercise is the correct one, then you've already been given the answer!
Click to expand...
so is this it (5x +2) ( 3x +4)
im sorry im pretty lost when we do it in class i follow rite along and i think i got it and then i get home and find myself lost.
 
jenzbears said:
so is this it (5x +2) ( 3x +4)
Click to expand...
Follow the instructions you were given earlier:

Multiply your answer out. If you get what you'd started with, your factorization must be right! :D

Eliz.
 
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