J justjoz New member Joined Dec 6, 2006 Messages 2 Dec 6, 2006 #1 Alright, the problem goes like this, but I KNOW it's wrong, can anyone help me by telling me where I went wrong? 8x^3=0 92x+3)(4x^2+6x+9)=0 x=3/2
Alright, the problem goes like this, but I KNOW it's wrong, can anyone help me by telling me where I went wrong? 8x^3=0 92x+3)(4x^2+6x+9)=0 x=3/2
J justjoz New member Joined Dec 6, 2006 Messages 2 Dec 6, 2006 #2 I goofed on that equation, it's supposed to be 8x^3 - 27 = 0 ( 2x + 3 ) ( 4x^2 + 6x + 9 ) x= 3/2
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Dec 6, 2006 #3 ...or not. s/b 2x-3 (+3)*(+9) = (+27) No good.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Dec 6, 2006 #4 justjoz said: 8x^3 - 27 = 0 ( 2x + 3 ) ( 4x^2 + 6x + 9 ) Click to expand... You might want to review the sum- and difference-of-cubes formulas, as you appear to have memorized them incorrectly. Eliz.
justjoz said: 8x^3 - 27 = 0 ( 2x + 3 ) ( 4x^2 + 6x + 9 ) Click to expand... You might want to review the sum- and difference-of-cubes formulas, as you appear to have memorized them incorrectly. Eliz.
