Factoring polynomial

Hi Lisa!

Ok, first, I want you to know that it makes life just a bit easier if you actually write out your equation like this...
9x<sup>3</sup> + 39x<sup>2</sup> + 12 =

In case you don't know how to do this, all you have to do is write 9x then < sup> without the space and then write the number that you want to be up, in this case it's 3, and then end it by writing </ sup> without the space. This makes it look like this : 9x<sup>3</sup>.
 
To "solve", we need whatever is on the other side of the "equals" sign. Is it "zero", or something else?

Thank you.

Eliz.
 
That cubic has no rational zeros.
. . I'll bet there's a typo . . .


How about:   9x3+39x2+12x=0\displaystyle \;9x^3\,+\,39x^2\,+\,12x\:=\:0 ?

. . Factor:   3x(x2+13x+4)=0\displaystyle \;3x(x^2\,+\,13x\,+\,4)\:=\:0

. . Factor:   3x(x+4)(3x+1)=0\displaystyle \;3x(x\,+\,4)(3x\,+\,1)\:=\:0

Therefore:   x=0,4,13\displaystyle \;x\,=\,0,\,-4,\,-\frac{1}{3}
 
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