S Simonsky Junior Member Joined Jul 4, 2017 Messages 128 Apr 30, 2018 #1 Could anyone help me with the technique for factorising these-don't have a clue how to do it: (p+1)^2 + 2(p+1) and (2q+3)^3+(2q+3)^2 Thanks
Could anyone help me with the technique for factorising these-don't have a clue how to do it: (p+1)^2 + 2(p+1) and (2q+3)^3+(2q+3)^2 Thanks
D Deleted member 4993 Guest Apr 30, 2018 #2 Simonsky said: Could anyone help me with the technique for factorising these-don't have a clue how to do it: (p+1)^2 + 2(p+1) and (2q+3)^3+(2q+3)^2 Thanks Click to expand... Can you factorize: x^2 + x and y^3 + y^2 ?
Simonsky said: Could anyone help me with the technique for factorising these-don't have a clue how to do it: (p+1)^2 + 2(p+1) and (2q+3)^3+(2q+3)^2 Thanks Click to expand... Can you factorize: x^2 + x and y^3 + y^2 ?
Steven G Elite Member Joined Dec 30, 2014 Messages 14,605 Apr 30, 2018 #3 Simonsky said: Could anyone help me with the technique for factorising these-don't have a clue how to do it: (p+1)^2 + 2(p+1) and (2q+3)^3+(2q+3)^2 Thanks Click to expand... When you have no idea, then look at definitions! (p+1)2 + 2(p+1) = (p+1)(p+1) + 2(p+1) = (p+1)(p+1) + 2(p+1). Can you factor from here?
Simonsky said: Could anyone help me with the technique for factorising these-don't have a clue how to do it: (p+1)^2 + 2(p+1) and (2q+3)^3+(2q+3)^2 Thanks Click to expand... When you have no idea, then look at definitions! (p+1)2 + 2(p+1) = (p+1)(p+1) + 2(p+1) = (p+1)(p+1) + 2(p+1). Can you factor from here?