factorizing completely pls help T.T

[nat.c]

[a-b]*2-a[a+4]

 

[Harry_the_cat]

Can you expand it out first ? ie get rid of the brackets

 

[Deleted member 4993]

[a-b]*2-a[a+4]

After expansion, you should get a quadratic in 'a'.

 

[HallsofIvy]

Actually, you won't "get a quadratic in a" because there will be two "a²" terms that cancel! You will get a quadratic in b.

 

[Deleted member 4993]

Actually, you won't "get a quadratic in a" because there will be two "a²" terms that cancel! You will get a quadratic in b.

That is incorrect.

The original post was:

[a-b]*2-a[a+4]

Expansion of the first term provides:

[a-b]*2 = 2*a - 2*b

There was no "a²" in the first term.

 

[HallsofIvy]

True but I'll bet (a- b)^2 was intended!

nat.c, was it "a- b times 2" or "a- b squared"?

 

[lookagain]

[a-b]*2-a[a+4]

nat.c, are you intending to square [a - b] or just multiply it by 2? Please get back to us,
because we cannot answer specifically to your question without a clarification.

 

[Dr.Peterson]

[a-b]*2-a[a+4]

No matter which way we take it, I don't see an interesting factorization. There may be another typo, or missing information that was provided in the problem. An image of the entire problem would be useful.

I'm also curious: What does T.T mean?