The function f is such that f(x)=a-bcosx for 0<= x<= 360, where a and b are positive constants.
The maximum value of f(x) is 10 and -2 at minimum.
Find a and b.
My workings
Solving for a:
10=a-bcosx
-a=-bcosx-10
a=bcosx+10
Solving for b:
-2=a-bcosx
0=a-bcosx+2
bcosx=a+2
[FONT="]b=acos(x)^-1+2cos(x)^-1[/FONT][FONT="].[/FONT][FONT="]
[/FONT][FONT="]Plug a into b:
b=(bcos(x)+10)cos(x)^-1+2cos(x)^-1
b=b+10cos(x)^-1+2cos(x)^-1
b=12cos(x)^-1+b
0=12cos(x)
( this is whe[/FONT]re I am stuck, assuming I am right with all my calculations)
If anyone could please help:?:
The maximum value of f(x) is 10 and -2 at minimum.
Find a and b.
My workings
Solving for a:
10=a-bcosx
-a=-bcosx-10
a=bcosx+10
Solving for b:
-2=a-bcosx
0=a-bcosx+2
bcosx=a+2
[FONT="]b=acos(x)^-1+2cos(x)^-1[/FONT][FONT="].[/FONT][FONT="]
[/FONT][FONT="]Plug a into b:
b=(bcos(x)+10)cos(x)^-1+2cos(x)^-1
b=b+10cos(x)^-1+2cos(x)^-1
b=12cos(x)^-1+b
0=12cos(x)
( this is whe[/FONT]re I am stuck, assuming I am right with all my calculations)
If anyone could please help:?: