find a,b,and c

[NEHA]

 

[pka]

We know from vertival angles:
\(\displaystyle \begin{array}{l}
b = c\quad \& \quad a = b + c \\
a + c + \left( {b + c} \right) + b = 360 \\
\end{array}\)

 

[NEHA]

We know from vertival angles:
\(\displaystyle \begin{array}{l}
b = c\quad \& \quad a = b + c \\
a + c + \left( {b + c} \right) + b = 360 \\
\end{array}\)

yes i know that.. but they are asking for
teh exact answers for a b and c
so if b = c and a = b + c
then......i know how to do it.....but
ok a doenst look like 90 degrees

 

[stapel]

yes i know that.. but they are asking for
teh exact answers for a b and c

In the future, it would be very helpful if you started showing what you already have. This has been requested so that the tutors don't waste your time telling you what you already know.

Since you already have the three linear equations, then take those equations and solve the linear system for the values of a, b, and c.

i know how to do it.....but ok a doenst look like 90 degrees

You know how to do what? When did "pka" say that m(a) = 90°? Please clearly explain your work and reasoning.

Thank you for your consideration.

Eliz.

P.S. It might also be helpful if you would kindly do us the courtesy of writing in standard English. Not everybody is fluent in kiddie chat-speak, and it is generally considered polite to speak clearly, with punctuation and capitalization and such, when requesting that others do you favors. Thank you.

 

[pka]

And one more thing in addition to what Ms Stapel wrote.
I gave three linear equations in three unknowns.
Solve them and you will have the answer to this question.

 

[NEHA]

reply

3b + 3c = 360
b + c = 120
b = c
2c = 120 or c = 60
c = 60
b = 60
60 + 60 = 120
a = 120

 

[stapel]

3b + 3c = 360

Where did this equation come from?

Thank you.

Eliz.

 

[2teachis2love4ever]

b=c and a=b+c

I think it came from the angle (b+c) and he substituted (b+c) in for a, so that equals 2b+2c. Then he added the b and c angles, therefore 3b + 3c = 360.