jenzbears said:
u]4x^2- 11xy-3y^2 y^2 + 4xy - 5x^2 5x^2-14xy-3Y^2
______________________.__________________divide by ______________
y^2 + 3xy-4x^2 8x^2 + 6xy + y^2 8x^2 = 2xy - y^2[/code][/u]
I think you might mean the following, assuming that you actually mean "Y" and "y" to be the same variable:
. . . . .[ (4x^2 - 11xy - 3y^2) / (y^2 + 3xy - 4x^2) ]
. . . . . . . . . .* [ (y^2 + 4xy - 5x^2) / (8x^2 + 6xy + y^2) ]
. . . . . . . . . . . . . . . / [ (5x^2 - 14xy - 3y^2) / (8x^2 - 2xy - y^2) ]
This may also be formatted as:
. . . . .\(\displaystyle \L \frac{4x^2\, -\, 11xy\, -\, 3y^2}{y^2\, +\, 3xy\, -\, 4x^2}\,\, \times\,\, \frac{y^2\, +\, 4xy\, -\, 5x^2}{8x^2\, +\, 6xy\, +\, y^2}\,\, \div\,\, \frac{5x^2\, -\, 14xy\, -\, 3y^2}{8x^2\, -\, 2xy\, -\, y^2}\)
Please reply with corrections or confirmation. When you reply, please show all of the work you have done so far, starting with your factorizations.
Thank you!
Eliz.