Find Area of Rhombus?

iosman123

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Jul 25, 2019
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Hello,

What is the area of rhombus ABCD if AB = 13 inches and AC = 10 inches?

I was told to use the formula:

A = 1/2 TIMES (diagonal one * (diagonal two)) However, I cannot find the right answer.

thanks
iosman
 
Hello,

What is the area of rhombus ABCD if AB = 13 inches and AC = 10 inches?

I was told to use the formula:

A = 1/2 TIMES (diagonal one * (diagonal two)) However, I cannot find the right answer.

thanks iosman
Rhombus has 4 equal sides. So either AC or AB is measure of diagonal.

Which is it?

Please share your work - with a sketch of ABCD attached - so that we know where does your mistake lie.....
 
I would assume if he rhombus is labelled conventionally, then AB is a side and AC is a diagonal. Is that correct, iosman?

Have you drawn a diagram?
Have you drawn in the other diagonal BD?
What is a special property of the diagonals of a rhombus?
Can you find the length of the diagonal BD?

Once you've answered those questions you should be able to put it together.
 
What is the area of rhombus ABCD if AB = 13 inches and AC = 10 inches?
A = 1/2 TIMES (diagonal one * (diagonal two)) However, I cannot find the right answer.
Go to this LINK and use the diagram there.
In this problem \(\displaystyle \bf{a}=13\) because the diagonals are perpendicular bisectors of each other, \(\displaystyle |\overline{AS}|=5\).
With those two values you can find \(\displaystyle |\overline{DS}|=?\)
 
What is the area of rhombus ABCD if AB = 13 inches and AC = 10 inches?

Ok i can imagine when we say ABCD this indicates AB is one of the sides and AC is the diagonal.
Now you probably know in rhombus , the two diagonals are perpendicular and cut each other in half. Now if you draw the two diagonals you will end up with 4 “———” triangles which then by knowing that they cut each other in half, you should be able to solve the problem.
 
ar of rhombus ==> 1/2(diag1*diag2)
point of intersection makes right angles
diag 1= 24
diag 2=32
ar == 1/2(32*24)
 
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