Find Area of Triangle A'B'C'

G

Guest

Guest
The vertices of triangle ABC are A(-4,7), B(3,-2) and C(8,-2). After a translation that maps (x,y) onto (x+h, y+k), triangle A'B'C' is the image of triangle ABC.

If triangle A"B"C" is the image of triangle ABC, after a DILATION using a scale factor of 2 with respect to the origin, how many square units are in the area of triangle A"B"C"?

What are the steps to solving this problem?

I found the area to be 120 but the book's answer is 90 for the area.

Can someone give me the steps needed for me to find the area on my own?
 
the 3 points become A'' -8,14
B'' 6,-4
C'' 16,-4

"base"= 16-6=10
"altitude"=14-[-4]=18

area=1/2[10]times18
area=90
Arthur
 
Top