hi all!
was doing this in homework
find the equation line through (1,2,3) and perpendicular to (3-2t,5+8t,7-4t) and (-2t, 5+t, 7-t).
thought it would be easy enough. crossed the two vectors to get a vector parallel to (1,2,3) however when i computed the cross product
i got quadratic equations.
the coefficient of the t^2 term in each quadratic given the correct t(a , b , c) to write my equation in the form of r(t) = (1,2,3) + t(a,b,c)
i dont understand what i did wrong here because it seems awfully incorrect to just use one coefficient and ignore the rest of the equation.
any help appreciated!
was doing this in homework
find the equation line through (1,2,3) and perpendicular to (3-2t,5+8t,7-4t) and (-2t, 5+t, 7-t).
thought it would be easy enough. crossed the two vectors to get a vector parallel to (1,2,3) however when i computed the cross product
i got quadratic equations.
the coefficient of the t^2 term in each quadratic given the correct t(a , b , c) to write my equation in the form of r(t) = (1,2,3) + t(a,b,c)
i dont understand what i did wrong here because it seems awfully incorrect to just use one coefficient and ignore the rest of the equation.
any help appreciated!