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Guest
Guest
Find an equation that relates x and y so that (x, y) is equidistant from the two given points: (3, 5/2) and (-7, 1)
I'm really unsure on how to do this. This is my work on how I attempted it:
D= (sqrt(x_2 - x_1)^2 + (y_2 - y_1)^2)
= (sqrt(x-3)^2 + (y-5/2)^2) ^2
= x^2 - 6x +9 +y^2 -5y +25
= (x^2-6x+y^2-5y+61/4) 4
= 4x^24x+4y^2-20y+61
D_2 = (sqrt(x+7)^2 + (y-1)^2) ^2
=x^2+14x +49+y^2-2y+1
=x^2 +14x+y^2-2y+50
Then I set these 2 equations equal to each other and subtracted the second one from the first one and got:
3x^2-38x+3y^2-18y+11
I don't know if this is right on how to do it. If it is, I'm unsure of what to do next because I think the final equation needs to be in the form mx-my-m=0 (where m is some number).
I'm really unsure on how to do this. This is my work on how I attempted it:
D= (sqrt(x_2 - x_1)^2 + (y_2 - y_1)^2)
= (sqrt(x-3)^2 + (y-5/2)^2) ^2
= x^2 - 6x +9 +y^2 -5y +25
= (x^2-6x+y^2-5y+61/4) 4
= 4x^24x+4y^2-20y+61
D_2 = (sqrt(x+7)^2 + (y-1)^2) ^2
=x^2+14x +49+y^2-2y+1
=x^2 +14x+y^2-2y+50
Then I set these 2 equations equal to each other and subtracted the second one from the first one and got:
3x^2-38x+3y^2-18y+11
I don't know if this is right on how to do it. If it is, I'm unsure of what to do next because I think the final equation needs to be in the form mx-my-m=0 (where m is some number).
