Hattie Gilmore
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- Joined
- Nov 4, 2007
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Find the equation of the line that contains the point (-2,4) and has a slope -2/3
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find equation of line through (-2, 4) having slope -2/3
- Thread starter Hattie Gilmore
- Start date
Find the equation of the line that contains the point (-2,4) and has a slope -2/3
m=-2/3,.....\(\displaystyle x_1=-2\),.....\(\displaystyle y_1=4\)
Use \(\displaystyle y-y_1 = m(x-x_1)\)
And next time please show us what you have done so far.
m=-2/3,.....\(\displaystyle x_1=-2\),.....\(\displaystyle y_1=4\)
Use \(\displaystyle y-y_1 = m(x-x_1)\)
And next time please show us what you have done so far.
Re: algebra problem
You could start with the "slope-intercept form" of the equation of a line:
y = mx + b
"m" is the slope, and "b" is the y-intercept of the line. You know that the slope is -2/3, so you could begin by substituting that for "m":
y = (-2/3)x + b
Now, you know that the point (-2, 4) is on the line. So, you can substitute -2 for x, and 4 for y:
4 = (-2/3)(-2) + b
4 = (4/3) + b
4 - (4/3) = b
(12/3) - (4/3) = b
8/3 = b
So...the equation of the line (in slope-intercept form) is
y = (-2/3)x + (8/3)
Hattie Gilmore said:Find the equation of the line that contains the point (-2,4) and has a slope -2/3
You could start with the "slope-intercept form" of the equation of a line:
y = mx + b
"m" is the slope, and "b" is the y-intercept of the line. You know that the slope is -2/3, so you could begin by substituting that for "m":
y = (-2/3)x + b
Now, you know that the point (-2, 4) is on the line. So, you can substitute -2 for x, and 4 for y:
4 = (-2/3)(-2) + b
4 = (4/3) + b
4 - (4/3) = b
(12/3) - (4/3) = b
8/3 = b
So...the equation of the line (in slope-intercept form) is
y = (-2/3)x + (8/3)