find indefinite integral

[Ashley5]

(7^3square root of x^4 - 2/square root of x) dx
du=x^4
dx=4x^3


Could someone help me finish this problem. Thank you

 

[tkhunny]

\(\displaystyle \frac{7^{3\sqrt{x^{4}-2}}}{\sqrt{x}}\)?

 

[Ashley5]

yes, sorry I didn't know how to type it.

 

[tkhunny]

You're kidding!? Why do you think you need to find this anitderivative? Can you supply the complete problem statement?

 

[Deleted member 4993]

\(\displaystyle \frac{7^{3\sqrt{x^{4}-2}}}{\sqrt{x}}\)?

or is it:

\(\displaystyle \frac{7^{3}\cdot\ \sqrt{x^{4}-2}}{\sqrt{x}}\)

 

[galactus]

Without proper grouping symbols(or better yet, LaTex) it's difficult for us to tell what you mean.

\(\displaystyle 7^{3}\int\frac{\sqrt{x^{4}-2}}{\sqrt{x}}dx\) is not easily integrated.

Perhaps you mean:

\(\displaystyle 7^{3}\int[\sqrt{x^{4}}-\frac{2}{\sqrt{x}}}]dx\)?.