find inverse of f(x) = 3 over 5x + 7, solve 2(7+3x)=1/4th

[callie2291]

1. find the inverse of the one to one function.

f(x)=3 over 5x+7

2. Solve the Equation 2(7+3x) = 1/4th
Solve equations of the Form b^x = b^y

3. Write the expression as sums or differences of multiple logarithms
Log (base 4) square root 11x

im sorry if they dont make sense

 

[tkhunny]

Re: new problem

1. find the inverse of the one to one function.

f(x)=3 over 5x+7

2. Solve the Equation 2(7+3x) = 1/4th
Solve equations of the Form b^x = b^y

3. Write the expression as sums or differences of multiple logarithms
Log (base 4) square root 11x

im sorry if they dont make sense

You have to give us SOMETHING callie2291. No work at all makes it impossible to know anything about how to help you.

Have you had algebra? Did you pass?

Have you read the "Forum Help" so that you can communicate better?

1) y = 3/(5x+7)

Solve for x.

2) This one makes no sense.

3) You have basic log rules. Use them.

log(a^b) = b*log(a) <== How does this relate to your square root?

log(a*b) = log(a)*log(b) <== How does this relate to your 11x?