ashloveskyle
New member
- Joined
- Oct 22, 2007
- Messages
- 1
how do you solve:
find the length,x, of the square one must cut out of the corners in order for the volume of the box to equal the surface area of the outside of the box. Explain and/or show how you arrived at your answer.
volume=4x^3-88x^2+448x
surface area = -4x^2-88x+536
find the length,x, of the square one must cut out of the corners in order for the volume of the box to equal the surface area of the outside of the box. Explain and/or show how you arrived at your answer.
volume=4x^3-88x^2+448x
surface area = -4x^2-88x+536