Hi everyone,
I have a right triangle with one leg measuring 9 and the hypotenuse measuring 15. I want to:
1. Find the length of the other leg using the Pythagorean theorem.
2. Find sin(θ) and cos(θ), where θ is the angle opposite the 9-unit leg.
My attempt:
- Using a^2 + b^2 = c^2 with a = 9, c = 15, and b unknown:
9^2 + b^2 = 15^2
81 + b^2 = 225
b^2 = 144 → b = 12
- For θ opposite the 9-unit leg:
sin(θ) = opposite/hypotenuse = 9/15 = 3/5
cos(θ) = adjacent/hypotenuse = 12/15 = 4/5
Does this look correct? If there’s a cleaner way to present or check the trig ratios, I’d appreciate suggestions. Thanks!
I have a right triangle with one leg measuring 9 and the hypotenuse measuring 15. I want to:
1. Find the length of the other leg using the Pythagorean theorem.
2. Find sin(θ) and cos(θ), where θ is the angle opposite the 9-unit leg.
My attempt:
- Using a^2 + b^2 = c^2 with a = 9, c = 15, and b unknown:
9^2 + b^2 = 15^2
81 + b^2 = 225
b^2 = 144 → b = 12
- For θ opposite the 9-unit leg:
sin(θ) = opposite/hypotenuse = 9/15 = 3/5
cos(θ) = adjacent/hypotenuse = 12/15 = 4/5
Does this look correct? If there’s a cleaner way to present or check the trig ratios, I’d appreciate suggestions. Thanks!