- Thread starter harpazo
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Can you please show me what you mean using the graph below. I will then return to the textbook to solve similar problems following your steps here.Oh, from the graph. You find one full period of the graph and subtract the x-valus from the start and finish of that period. Take the absolute value of that difference.

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See (0,0) is on the graph. After one full cycle, or S shape, we get to the point (2pi,0).

What distance is that on the x-axis? 2pi. So the period is 2pi.

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On this one, I'd look at (0, 3) and (8, 3). That's a full cycle so period is 8.Can you please show me what you mean using the graph below. I will then return to the textbook to solve similar problems following your steps here.

View attachment 19115

It doesnt matter what two points you look at, as long as there is a full cycle between them. For example, (4, -3) and (12,-3). Period is still 8.

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One period starts at 0 and finishes at 8. Another period/cycle starts at 4 and finishes at 12. Another one starts at starts at -4 and finishes at 4. Just take any of those and subtract the end values. For example 8-0 = 8, 12-4 = 8, 4-(-4) = 8. The length of the period is 8.Can you please show me what you mean using the graph below. I will then return to the textbook to solve similar problems following your steps here.

View attachment 19115

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I totally get it. Use the distance formula for points. Thanks.

What distance is that on the x-axis? 2pi. So the period is 2pi.

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Very good. Thanks.One period starts at 0 and finishes at 8. Another period/cycle starts at 4 and finishes at 12. Another one starts at starts at -4 and finishes at 4. Just take any of those and subtract the end values. For example 8-0 = 8, 12-4 = 8, 4-(-4) = 8. The length of the period is 8.