B btw New member Joined Nov 11, 2017 Messages 1 Nov 11, 2017 #1 Find all possible values of x, such that . . .\(\displaystyle (5^x\, -\, 2^x\, +\, 3)^3\, =\, (5^x\, -\, 5)^3\, -\, (2^x\, -\, 8)^3\) Attachments Screenshot_3.jpg 7.8 KB · Views: 10 Last edited by a moderator: Nov 14, 2017
Find all possible values of x, such that . . .\(\displaystyle (5^x\, -\, 2^x\, +\, 3)^3\, =\, (5^x\, -\, 5)^3\, -\, (2^x\, -\, 8)^3\)
D Deleted member 4993 Guest Nov 12, 2017 #2 btw said: Find all possible values of x, such that . . .\(\displaystyle (5^x\, -\, 2^x\, +\, 3)^3\, =\, (5^x\, -\, 5)^3\, -\, (2^x\, -\, 8)^3\) Click to expand... Hint: (a - b)^3 = a^3 - b^3 - 3ba^2 + 3ab^2 ......... sign error fixed and 3 = -5 - (-8) What are your thoughts? Please share your work with us ...even if you know it is wrong. If you are stuck at the beginning tell us and we'll start with the definitions. You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL: http://www.freemathhelp.com/forum/announcement.php?f=33 Last edited by a moderator: Nov 14, 2017
btw said: Find all possible values of x, such that . . .\(\displaystyle (5^x\, -\, 2^x\, +\, 3)^3\, =\, (5^x\, -\, 5)^3\, -\, (2^x\, -\, 8)^3\) Click to expand... Hint: (a - b)^3 = a^3 - b^3 - 3ba^2 + 3ab^2 ......... sign error fixed and 3 = -5 - (-8) What are your thoughts? Please share your work with us ...even if you know it is wrong. If you are stuck at the beginning tell us and we'll start with the definitions. You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL: http://www.freemathhelp.com/forum/announcement.php?f=33
