find real numbers x such that 27^x > 9^(x^2)

[Math wiz ya rite 09]

Find all real numbers x such that:

27^x > 9^(x^2)

Thanks

 

[pka]

This is what you need to know:
\(\displaystyle \L 27^x = 3^{3x} \quad \& \quad 9^{x^2 } = 3^{2x^2 } .\)