Find Slope, X and Y intercepts and Graph of -4x+10Y=-40

lotus

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Find Slope, X and Y intercepts and Graph

-4x+10Y=-40

I attached a photo with my work and I want to know if I am correct. Thank You.
 

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Find Slope, X and Y intercepts and Graph

-4x+10Y=-40

I attached a photo with my work and I want to know if I am correct. Thank You.
The photo is a bit hard for me to read.

\(\displaystyle -\ 4x + 10y = -\ 40 \implies y = \dfrac{4x}{10} - 4 = \left ( \dfrac{4}{10} \right )x - 4.\)

So the slope is \(\displaystyle \dfrac{4}{10} = 0.4.\)

\(\displaystyle x = 0\ and\ y = \dfrac{4x}{10} - 4 \implies y = -\ 4.\)

So the y-intercept is \(\displaystyle -\ 4.\)

\(\displaystyle y = 0\ and\ y = \dfrac{4x}{10} - 4 \implies 0 = \dfrac{4x}{10} - 4 \implies\)

\(\displaystyle 10 * 0 = 10 * \left ( \dfrac{4x}{10} - 4 \right ) \implies 4x - 40 = 0 \implies 4x = 40 \implies x = 10.\)

So the x-intercept is \(\displaystyle 10.\)
 
Your working finding the slope-intercept form is correct, but be careful how you write 4x/10. It kinda looks like you wrote x in the denominator.

Also, you saw the y-intercept from the slope-intercept form (and wrote it down), so there's no need to recalculate it using the original equation.

Lastly, you correctly substituted y=0 into the original (for finding the x-intercept), but you forgot to copy the negative sign in front of -4x. That's why you got (-10,0) instead of (10,0). :)

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