Find the cube roots of -64i in 'a + bi' form

[Robert G]

Hey guys, I have a problem concerning complex numbers and I could very much use your help. Please help me with it. I need to:

Find the cube roots of -64i in the form of a+bi with a and b being real.

Thank you for your help in advance.

 

[stapel]

Find the cube roots of -64i in the form of a+bi with a and b being real.

What formulas do you have? What have you tried? How far have you gotten? Where are you stuck?

Please be specific. Thank you!

Eliz.

 

[Deleted member 4993]

Use the identity

$\displaystyle -i = e^{(-i\frac{\pi}{2})}$