R Robert G New member Joined Dec 1, 2007 Messages 6 Jan 12, 2008 #1 Hey guys, I have a problem concerning complex numbers and I could very much use your help. Please help me with it. I need to: Find the cube roots of -64i in the form of a+bi with a and b being real. Thank you for your help in advance.
Hey guys, I have a problem concerning complex numbers and I could very much use your help. Please help me with it. I need to: Find the cube roots of -64i in the form of a+bi with a and b being real. Thank you for your help in advance.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Jan 12, 2008 #2 Robert G said: Find the cube roots of -64i in the form of a+bi with a and b being real. Click to expand... What formulas do you have? What have you tried? How far have you gotten? Where are you stuck? Please be specific. Thank you! Eliz.
Robert G said: Find the cube roots of -64i in the form of a+bi with a and b being real. Click to expand... What formulas do you have? What have you tried? How far have you gotten? Where are you stuck? Please be specific. Thank you! Eliz.
D Deleted member 4993 Guest Jan 12, 2008 #3 Use the identity \(\displaystyle -i = e^{(-i\frac{\pi}{2})}\)