coolbeans33
New member
- Joined
- Sep 19, 2013
- Messages
- 10
how do you get the derivative of g(x)= square root of 1+2x? please explain the steps for how you got the answer. my book says that it's 1/(sqrt 1+2x). this doesn't make any sense to me.
it's also asking for the domain of g(x) and the domain of g'(x). I thought the domain for g(x) would be x is greater than or equal to zero, but apparently I'm wrong.
it's also asking for the domain of g(x) and the domain of g'(x). I thought the domain for g(x) would be x is greater than or equal to zero, but apparently I'm wrong.