If I were to do this problem,
as along as we are given the right angle of the length d, this can be solve in many waysYes, I suppose we should confirm that \(\displaystyle \angle ABC\) is a right angle.
You could do it using Pythagoras' Theorem, but it doesn't appear the easiest method:as along as we are given the right angle of the length d, this can be solve in many ways
it can be solved as Khan said, similar triangles
It can be solved by your way lex, area and height
and finally and the easiest one is just Pythagorean
lolYou could do it using Pythagoras' Theorem, but it doesn't appear the easiest method:
Add the label \(E\) as the foot of the altitude from \(B\) so \(BE=d\). Now \(d\) is a mean proportional between \(AE~\&~CE\)This was some advanced math showed to our class by our teacher and I would like to get it solved if possible.
So the task is to find the length of d and all the picture has all the information that was given to us. There's no hurry.
No - there's only one equation to be solved! For the area of the triangle ABC:No no .... with "areas" you have to solve two equations.... I win.....