Find the local exterma-Logarithms

[wind]

Hi can someone check over my work? Thanks

Find the local exterma

\(\displaystyle \L\ y=xlnx\)

\(\displaystyle \L\frac{dy}{dx}=(1)(lnx)+(x)(\frac{1}{x})\)

\(\displaystyle \L\ 0=lnx+1\)

\(\displaystyle \L\ -1=lnx\)

\(\displaystyle \L\ -1=log_{e}x\)

\(\displaystyle \L\ e^{-1}=x\)

\(\displaystyle \L\frac{1}{e}=x\)

 

[galactus]

You are correct.

 

[wind]

Thanks, galactus

 

[skeeter]

you found the location (x-value) of the extrema, not the extrema.

extrema are function values ... it is important to note the difference.

the extrema is f(1/e) = -1/e