Find the radius of a circle, given its diameter

[LiseyDot05]

So he says radius is ½ the diameter

But he's struggling with how to work out Circle 4. Any suggestions to point him in the right direction?

Thanks in advance.

 

[BigBeachBanana]

Circle 1&2 are similar. How did he work that out?

 

[topsquark]

So he says radius is ½ the diameter

But he's struggling with how to work out Circle 4. Any suggestions to point him in the right direction?

Thanks in advance.View attachment 36487

Are the answers supposed to be given in decimal format, or mixed number? There's a mix of both there.

If decimal answers are acceptable then simply: [imath]3 \, \dfrac{7}{8} = 3.875[/imath], and then just divide by 2.

If mixed numbers are to be used, then
[imath]3 \, \dfrac{7}{8}[/imath] divided by 2 is

[imath]\dfrac{3}{2} \, \dfrac{7}{16} = 1 + \dfrac{1}{2} + \dfrac{7}{16}[/imath]

and now just add the fractions.

Can you finish?

-Dan

 

[LiseyDot05]

Are the answers supposed to be given in decimal format, or mixed number? There's a mix of both there.

If decimal answers are acceptable then simply: [imath]3 \, \dfrac{7}{8} = 3.875[/imath], and then just divide by 2.

If mixed numbers are to be used, then
[imath]3 \, \dfrac{7}{8}[/imath] divided by 2 is

[imath]\dfrac{3}{2} \, \dfrac{7}{16} = 1 + \dfrac{1}{2} + \dfrac{7}{16}[/imath]

and now just add the fractions.

Can you finish?

-Dan

It doesn't state how the answers should be given I'm afraid.

 

[LiseyDot05]

I think we have finally found a method to our madness.

 

[pka]

[imath]3\frac{7}{8}=\dfrac{24+7}{8}=11.37\text{ or } 11\frac{3}{8}[/imath]

91/8= - Wolfram|Alpha

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www.wolframalpha.com

 

[lookagain]

[imath]3 \, \dfrac{7}{8}[/imath] divided by 2 is

[imath]\dfrac{3}{2} \, \dfrac{7}{16} = 1 + \dfrac{1}{2} + \dfrac{7}{16}[/imath]

You're missing a plus sign in the second line between the first two fractions.

\(\displaystyle 3 \,\dfrac{7}{8} \ \) divided by 2 is

\(\displaystyle \ \bigg(3 + \dfrac{7}{8}\bigg)\bigg(\dfrac{1}{2}\bigg) \ =\)

\(\displaystyle \dfrac{3}{2} + \dfrac{7}{16} \ = \)

\(\displaystyle 1 + \dfrac{1}{2} + \dfrac{7}{16}\)

 

[topsquark]

You're missing a plus sign in the second line between the first two fractions.

\(\displaystyle 3 \,\dfrac{7}{8} \ \) divided by 2 is

\(\displaystyle \ \bigg(3 + \dfrac{7}{8}\bigg)\bigg(\dfrac{1}{2}\bigg) \ =\)

\(\displaystyle \dfrac{3}{2} + \dfrac{7}{16} \ = \)

\(\displaystyle 1 + \dfrac{1}{2} + \dfrac{7}{16}\)

Technically, I suppose you are right. I was taking the mixed number [imath]3 \dfrac{7}{8}[/imath] and dividing each "component" by 2. I don't know if there is a standard way to write that.

But, either way, that was what I was going for.

-Dan