finding consecutive inteters

[vondava3]

Find four consecutive integers such that twice the largest plus the smallest is 20 more than three times the sum of the middle two integers.
Im lost.

2(n+3)+n=20+3(n+1+n+2) that is how (one of many) I had it set up. Can anyone help?

 

[stapel]

Your set-up is fine; you've done the hard part. :wink:

Now solve the linear equation "3n + 3 = 6n + 29" for the value of n. Back-solve to find the other three numbers.