Question : "Find the number of divisor of 1080 excluding the throughout divisors, which are perfect squares."
What I have done : I found the divisors of 1080 which is : 2x2x2x3x3x3x5 = 2^3 x 3^3 X 5
Let me be frank I understood that by excluding the perfect squares means I have to not count the 2^2 and so as 3^2. So I counted for total number of divisors is 2^0 x 2^1 x 3^0 x 3^1 x 5^0 x 5^1 =Considering powers (1+1) x (1+1) x (1+1) = 8 but answer is something different. I know I am mistaking in considering perfect square. Please clear my confusion so that I will able to count clearly. Thank you.
What I have done : I found the divisors of 1080 which is : 2x2x2x3x3x3x5 = 2^3 x 3^3 X 5
Let me be frank I understood that by excluding the perfect squares means I have to not count the 2^2 and so as 3^2. So I counted for total number of divisors is 2^0 x 2^1 x 3^0 x 3^1 x 5^0 x 5^1 =Considering powers (1+1) x (1+1) x (1+1) = 8 but answer is something different. I know I am mistaking in considering perfect square. Please clear my confusion so that I will able to count clearly. Thank you.
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