Finding fractions of a mixed number: solve 1 2/7 + 4/5 of 3 1/3

[Adsa2521]

1 2/7 + 4/5 of 3 1/3


Can someone explain the steps to solve this? I know how to simplify and divide fractions but think I must be doing this in wrong order...

 

[Otis]

Hi. I would (1) write the two mixed numbers as improper fractions, (2) do the multiplication by 4/5, (3) add that product to the first number and (4) write the answer as a mixed number.

If you're still not sure, then post your work so we can see what you're doing. If you have a question about any step, please ask.
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[Steven G]

In mathematics, of means to multiply.
So 4/5 of 3 1/3 means (4/5)*(3 1/3)

 

[pka]

1 2/7 + 4/5 of 3 1/3
Can someone explain the steps to solve this? I know how to simplify and divide fractions but think I must be doing this in wrong order...

Is the problem $1\tfrac{2}{7}+\left(\tfrac{4}{5}\right)\cdot\left(3\tfrac{1}{3}\right)~?$

 

[Shiloh]

I think this is ambiguous. [answer deleted - moderator]

 

[The Highlander]

I think this is ambiguous. [answer deleted - moderator]

I disagree completely; it doesn't look "ambiguous" at all, as clarified in the posts (#3 & #4) before your post!

But, regardless of however you "interpreted" it, you have (once again) supplied 'answers' to the question when the OP was being encouraged to make an effort to solve the problem themself, having been given adequate help in (all) the posts above yours!

It is thus difficult to avoid the suspicion that you simply wish to show that you can do it when the aim of the the forum is to provide help for (predominantly) new members to do the work on their own after getting suitable guidance (as was already provided in this case).

Please stop 'showing off', eh?

 

[Otis]

[The original post] could be interpreted as (1 2/7+ 4/5)(3 1/3)

Hi Shiloh. If we start adding grouping symbols to the original expression, then many different interpretations are possible. Unless Adsa responds by posting a new expression, I need to interpret their exercise using the Order of Operations.

PS: This forum has a policy that we don't post answers unless four days have passed since the student's most-recent post.
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[Steven G]

I think this is ambiguous. It could be interpreted as (1 2/7+ 4/5)(3 1/3)= (9/7+4/5)(10/3)= (45/35+ 28/35)(10/3)= (73/35)(10/3)= 730/105.
Or it could be interpreted as 1 2/7+ (4/5)(3 1/3)= 9/7+ (4/5)(10/3)= 9/7+ 8/3= 27/21+ 56/21= 83/21.

Since the original problem uses mixed numbers I do not think the final answers should have improper fractions!

Helpers here encourage new members to help out. We basically have two rules. Be correct most of the time and don't just give answers. You have been violating both rules.

 

[farhan]

To solve the expression 1 2/7 + 4/5 of 3 1/3, we need to follow the order of operations, which is PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

First, let's convert the mixed numbers to improper fractions: 1 2/7 = (71 + 2)/7 = 9/7 3 1/3 = (33 + 1)/3 = 10/3

Next, we'll find the product of 4/5 and 10/3: 4/5 * 10/3 = (410)/(53) = 8/3

Now, we can add 1 2/7 and 8/3 by finding a common denominator: 9/7 + 8/3 = (93)/(73) + 8/3 = 27/21 + 56/21 = 83/21

Finally, we can simplify the fraction 83/21 to a mixed number: 83 ÷ 21 = 3 with a remainder of 20 So, 83/21 = 3 20/21

Therefore, the solution to 1 2/7 + 4/5 of 3 1/3 is 3 20/21.

 

[lookagain]

To solve the expression 1 2/7 + 4/5 of 3 1/3, we need to follow the order of operations, which is PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

First, let's convert the mixed numbers to improper fractions: 1 2/7 = (71 + 2)/7 = 9/7 3 1/3 = (33 + 1)/3 = 10/3

Next, we'll find the product of 4/5 and 10/3: 4/5 * 10/3 = (410)/(53) = 8/3

Now, we can add 1 2/7 and 8/3 by finding a common denominator: 9/7 + 8/3 = (93)/(73) + 8/3 = 27/21 + 56/21 = 83/21

Finally, we can simplify the fraction 83/21 to a mixed number: 83 ÷ 21 = 3 with a remainder of 20 So, 83/21 = 3 20/21

Therefore, the solution to 1 2/7 + 4/5 of 3 1/3 is 3 20/21.

farhan, your post is wrong. You left out symbols for multiplication in almost all places. Using an asterisk or a multiplication dot are a couple of good examples to use. Your eighth line shows an inconsistent use, because 8/3 was not being shown converted to an equivalent fraction at the same that
9/7 was. Here is a partial redo:

1 2/7 = (7*1 + 2)/7 = 9/7
3 1/3 = (3*3 + 1)/3 = 10/3

(4/5)(10/3) = (4*10)/(5*3) = 40/15 = 8/3
9/7 + 8/3 = (9*3)/(7*3) + (8*7)/(3*7) = 27/21 + 56/21 = 83/21

83/21 = . . .