Finding fractions of a mixed number: solve 1 2/7 + 4/5 of 3 1/3
- Thread starter Adsa2521
- Start date
Otis
Elite Member
- Joined
- Apr 22, 2015
- Messages
- 4,414
Hi. I would (1) write the two mixed numbers as improper fractions, (2) do the multiplication by 4/5, (3) add that product to the first number and (4) write the answer as a mixed number.
If you're still not sure, then post your work so we can see what you're doing. If you have a question about any step, please ask.
[imath]\;[/imath]
If you're still not sure, then post your work so we can see what you're doing. If you have a question about any step, please ask.
[imath]\;[/imath]
pka
Elite Member
- Joined
- Jan 29, 2005
- Messages
- 11,971
Is the problem [imath]1\tfrac{2}{7}+\left(\tfrac{4}{5}\right)\cdot\left(3\tfrac{1}{3}\right)~?[/imath]
The Highlander
Full Member
- Joined
- Feb 18, 2022
- Messages
- 937
I disagree completely; it doesn't look "ambiguous" at all, as clarified in the posts (#3 & #4) before your post!
But, regardless of however you "interpreted" it, you have (once again) supplied 'answers' to the question when the OP was being encouraged to make an effort to solve the problem themself, having been given adequate help in (all) the posts above yours!
It is thus difficult to avoid the suspicion that you simply wish to show that you can do it when the aim of the the forum is to provide help for (predominantly) new members to do the work on their own after getting suitable guidance (as was already provided in this case).
Please stop 'showing off', eh?
Last edited by a moderator:
Otis
Elite Member
- Joined
- Apr 22, 2015
- Messages
- 4,414
Hi Shiloh. If we start adding grouping symbols to the original expression, then many different interpretations are possible. Unless Adsa responds by posting a new expression, I need to interpret their exercise using the Order of Operations.
PS: This forum has a policy that we don't post answers unless four days have passed since the student's most-recent post.
[imath]\;[/imath]
Steven G
Elite Member
- Joined
- Dec 30, 2014
- Messages
- 14,382
Since the original problem uses mixed numbers I do not think the final answers should have improper fractions!
Helpers here encourage new members to help out. We basically have two rules. Be correct most of the time and don't just give answers. You have been violating both rules.
To solve the expression 1 2/7 + 4/5 of 3 1/3, we need to follow the order of operations, which is PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).
First, let's convert the mixed numbers to improper fractions: 1 2/7 = (71 + 2)/7 = 9/7 3 1/3 = (33 + 1)/3 = 10/3
Next, we'll find the product of 4/5 and 10/3: 4/5 * 10/3 = (410)/(53) = 8/3
Now, we can add 1 2/7 and 8/3 by finding a common denominator: 9/7 + 8/3 = (93)/(73) + 8/3 = 27/21 + 56/21 = 83/21
Finally, we can simplify the fraction 83/21 to a mixed number: 83 ÷ 21 = 3 with a remainder of 20 So, 83/21 = 3 20/21
Therefore, the solution to 1 2/7 + 4/5 of 3 1/3 is 3 20/21.
First, let's convert the mixed numbers to improper fractions: 1 2/7 = (71 + 2)/7 = 9/7 3 1/3 = (33 + 1)/3 = 10/3
Next, we'll find the product of 4/5 and 10/3: 4/5 * 10/3 = (410)/(53) = 8/3
Now, we can add 1 2/7 and 8/3 by finding a common denominator: 9/7 + 8/3 = (93)/(73) + 8/3 = 27/21 + 56/21 = 83/21
Finally, we can simplify the fraction 83/21 to a mixed number: 83 ÷ 21 = 3 with a remainder of 20 So, 83/21 = 3 20/21
Therefore, the solution to 1 2/7 + 4/5 of 3 1/3 is 3 20/21.
farhan, your post is wrong. You left out symbols for multiplication in almost all places. Using an asterisk or a multiplication dot are a couple of good examples to use. Your eighth line shows an inconsistent use, because 8/3 was not being shown converted to an equivalent fraction at the same that
9/7 was. Here is a partial redo:
1 2/7 = (7*1 + 2)/7 = 9/7
3 1/3 = (3*3 + 1)/3 = 10/3
(4/5)(10/3) = (4*10)/(5*3) = 40/15 = 8/3
9/7 + 8/3 = (9*3)/(7*3) + (8*7)/(3*7) = 27/21 + 56/21 = 83/21
83/21 = . . .