What are your thoughts? What have you tried? How far have you gotten? Where are you stuck?
In other words, you drew the right triangle in the third quadrant, noted that both the x- and y-values will be negative, noted that the secant ratio is the reciprocal of the cosine ratio, used this information to label two of the sides of the right triangle, used the Pythagorean Theorem to find the length of the third side, and... then what?
Secant is "1 over cosine" or "hypotenuse over near side" or equivalently, on a unit circle, (x, y) such that x2+y2=1 and x=−5/13. Solve for y (in the third quadrant, y is also negative.)
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