C chabreya New member Joined Mar 5, 2007 Messages 5 Mar 5, 2007 #1 a triangle has a height that is 3 more than twice the base and the area is 45 square units. Find the base and heights
a triangle has a height that is 3 more than twice the base and the area is 45 square units. Find the base and heights
pka Elite Member Joined Jan 29, 2005 Messages 11,990 Mar 5, 2007 #2 \(\displaystyle \L \begin{array}{l} Area = \frac{{bh}}{2} \\ 45 = \frac{{b\left( {2b + 3} \right)}}{2} \\ \end{array}\)
\(\displaystyle \L \begin{array}{l} Area = \frac{{bh}}{2} \\ 45 = \frac{{b\left( {2b + 3} \right)}}{2} \\ \end{array}\)
C chabreya New member Joined Mar 5, 2007 Messages 5 Mar 5, 2007 #3 the answer i got is 2.5 =2b^2+3b. I know this is not right what am i doing wrong.
skeeter Elite Member Joined Dec 15, 2005 Messages 3,216 Mar 5, 2007 #4 wrong equation ... multiply both sides of pka's equation by 2, you get ... 90 = 2b<sup>2</sup> + 3b solve this quadratic equation ... remember that you're looking for a base distance.
wrong equation ... multiply both sides of pka's equation by 2, you get ... 90 = 2b<sup>2</sup> + 3b solve this quadratic equation ... remember that you're looking for a base distance.
