finding the derivative of p(x)= 10^6[1+(x-1)e^-(0.001x)]

[Guest]

Oi, How do you find the derivative of this:

p(x)= 10^6[1+(x-1)e^-(0.001x)]

so complicated -_-'

Thanks again for the help

 

[pka]

It is not complicated at all!
Just apply the product rule.\(\displaystyle \L
{\rm{y = 10}}^{\rm{6}} \left[ {1 + \left( {x - 1} \right)e^{ - 0.001x} } \right]\quad \Rightarrow \quad y' = {\rm{10}}^{\rm{6}} \left[ {e^{ - 0.001x} - 0.001\left( {x - 1} \right)e^{ - 0.001x} } \right]\)

 

[Guest]

but how come you left 10^6 like that? dont you have to find the derivative of that too? but it would give you zero which makes no sense

 

[stapel]

Hint: What is the derivative of y = 10⁶x?

Eliz.