NoGoodAtMath
New member
- Joined
- May 2, 2013
- Messages
- 35
I know the distance formula; d=√(x2-x1)^2 +(y2-y1)^2
So here is the problem:
(√5, -√2) and (4√5, -7√2)
d=√(4√5- √5)^2 + (-7√2- √2)^2
After this I have no idea. The square roots are tripping me up. What I did was took 3√5-5 and that became 15√5, then I multiplied 15(5) and got 75. Then I worked the other half. I got -8√2 -2 and that gave me and -32. I know I did something wrong here. Please me out. Thanks so much.
So here is the problem:
(√5, -√2) and (4√5, -7√2)
d=√(4√5- √5)^2 + (-7√2- √2)^2
After this I have no idea. The square roots are tripping me up. What I did was took 3√5-5 and that became 15√5, then I multiplied 15(5) and got 75. Then I worked the other half. I got -8√2 -2 and that gave me and -32. I know I did something wrong here. Please me out. Thanks so much.