Finding the Inverse of f(x) = (-2+2x)/(1+x)

hooolia

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Sep 24, 2007
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Let f(x) = (-2+2x)/(1+x)

This is as far as I can get:
y = (-2+2x)/(1+x)
(1+x)(y)=-2+2x

Now I'm supposed to continue to solve for (y) but I can't get the numbers to work. HELP PLEASE!!
 
\(\displaystyle \begin{array}{l}
y = \frac{{ - 2 + 2x}}{{1 + x}} \\
x = \frac{{ - 2 + 2y}}{{1 + y}}\;\mbox{change x with y} \\
\end{array}\)
Now solve for y!
 
Re: Finding the Inverse

hooolia said:
Let f(x) = (-2+2x)/(1+x)

This is as far as I can get:
y = (-2+2x)/(1+x)
(1+x)(y)=-2+2x

Now solve for 'x'

y + xy = -2 + 2x

y + 2 = x(2-y)

from above solve for x = g(y)

then interchange x and y to get y = g(x) - and yoy found your inverse!


Now I'm supposed to continue to solve for (y) but I can't get the numbers to work. HELP PLEASE!!
 
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