Finding the Minimum Interval of root Equation (Numerical Analysis)

[Ghayyas]

Im New to Numerical Analysis I got a problem, But I don't understand it.
Q: The Minimum interval in which root of the equation x² +3x+1=0 lie is
Options:
1) (0,1)
2) (1,2)
3) (2,4)
4) (0,2)
I think option 1 is correct But I have doubt Please help me to explain this problem.

Please explain Im really confused.

 

[pka]

Q: The Minimum interval in which root of the equation x² +3x+1=0 lie is
Options:
1) (0,1)
2) (1,2)
3) (2,4)
4) (0,2)

Please review what you posted. None of the intervals posted contains a root of that equation.
Is the equation actually \(\displaystyle x^2{\Large-}3x+1=0~?\) Or something else like that? SEE HERE

 

[Ghayyas]

Please review what you posted. None of the intervals posted contains a root of that equation.
Is the equation actually \(\displaystyle x^2{\Large-}3x+1=0~?\) Or something else like that? SEE HERE

Thanks for your Reply yes Actually write it wrong.
its x² - 3x +1=0

 

[pka]

Thanks for your Reply yes Actually write it wrong.
its x² - 3x +1=0

Have a look HERE Be careful. You you want the interval to contain all roots?

 

[Jagulba]

even with your correction one root is (approximately) 0.36 and the other is 2.6
which means the interval should be 0 to 3
if you can chose multiple then it would be option 1 and 3